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Even or Odd (8kyu) [Ruby]
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Description:
Create a function (or write a script in Shell) that takes an integer as an argument and returns "Even" for even numbers or "Odd" for odd numbers.
Solution 1
Let's use Modulo operator (%)
operator. It returns the remainder left over when one operand is divided by a second operand. It always takes the sign of the dividend.
4 % 2 // 0
3 % 2 // 1
If the number is even it returns 0 and if the number is odd it returns 1. Which converts to false or true accordingly.
def even_or_odd(number)
(number % 2 == 0) ? "Even" : "Odd"
end
Solution 2
Alternatively, we can create an array with 'Even' and 'Odd' values and return the first or second element.
def even_or_odd(number)
['Even', 'Odd'][number % 2]
end
Solution 3
Using even?
/odd?
methods.
def even_or_odd(number)
number.even? ? "Even" : "Odd"
end