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Square(n) Sum (8kyu) [JavaScript]
Chek kata on Codewars
Description:
Complete the square sum function so that it squares each number passed into it and then sums the results together.
For example, for [1, 2, 2] it should return 9 because 1^2 + 2^2 + 2^2 = 9.
A few ways to square a number
1 number * number
2 Math.pow(number, 2)
3 number **2
Loop
function squareSum(numbers) {
let sum = 0
for( let i = 0; i < numbers.length; i++) {
sum += numbers[i] **2
}
return sum
}
Reducer
function squareSum(numbers) {
const multiply = number => number * number
const reducer = (acc, cur) => acc + cur
return Array.from(numbers, multiply).reduce(reducer, 0)
}
function squareSum(numbers) {
return numbers.map(multiply).reduce(reducer, 0)
}
function multiply(number) {
return Math.pow(number, 2)
}
function reducer(acc, cur) {
return acc + cur
}
function squareSum(numbers) {
return numbers.reduce( (acc, cur) => acc + (cur **2), 0)
}
ForEach
function squareSum(numbers) {
let sum = 0
numbers.forEach( number => {
sum += (number * number)
})
return sum
}